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gan ane lg belajar C language dan ane dah googling tp msh bingung mengenai ampersand ini "&" Code: #include int main() { char name[20]; char color[20]; printf(�What is your name?�); scanf(�%s�,name); printf(�What is your favorite color?�); scanf(�%s�,color); printf(�%s�s favorite color is %s\n�,name,color); return(0); } tuh yang di atas kok ga usa pake &name atau &color ,outputnya ok2 aja tapi utk code di bawah ini harus pake , kalo ga pake output printf-nya ga muncul. Code: #include int main() { char key; puts(�Type your favorite keyboard character:�); scanf(�%c�,&key); printf(�Your favorite character is %c!\n�,key); return(0); } Dan ini hasil googling ane. Spoiler for buka: scanf() must have the address of the variable to store input into. This means that often the ampersand address operator is required to compute the addresses. Here's an example: int x; char * st = malloc(31); scanf("%d", &x); /* & required to pass address to scanf() */ scanf("%30s", st); /* NO & here, st itself points to variable! */ As the last line above shows, sometimes no ampersand is correct! maksudnya "& required to pass address to scanf()" itu kalo "x" nya ga ngepoint ke variable harus pake "&" ??? dan yang "scanf("%30s", st);" katanya no & here karena itu ngepoint ke variable dan di kode kedua diatas jg nge point ke variable "key" tetapi tanpa & malah ga jalan printf-nya. Mohon dibantu para sesepuh . Thanx. Terkait:
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